(x^2+4x-12)/(8-4x)

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Solution for (x^2+4x-12)/(8-4x) equation: 


D( x )

8-(4*x) = 0

8-(4*x) = 0

8-(4*x) = 0

8-4*x = 0

8-4*x = 0 // - 8

-4*x = -8 // : -4

x = -8/(-4)

x = 2

x in (-oo:2) U (2:+oo)

(x^2+4*x-12)/(8-(4*x)) = 0

(x^2+4*x-12)/(8-4*x) = 0

x^2+4*x-12 = 0

x^2+4*x-12 = 0

DELTA = 4^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-4)/(1*2) or x = (-64^(1/2)-4)/(1*2)

x = 2 or x = -6

(x+6)*(x-2) = 0

((x+6)*(x-2))/(8-4*x) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 2} 

x = -6

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